Res 341 Wk 5 E-Text

8.46 A random sample of 10 miniature Tootsie Rolls was interpreted from a bag. Each piece was weighed on a in truth accurate scale. The results in grams were 3.087 3.131 3.241 3.241 3.270 3.353 3.400 3.411 3.437 3.477 (a) defecate a 90 share faith detachment for the true mean slant. The standard computer error is E = 1.96(s/sqrt(n)) = 1.96[0.131989/sqrt(10)]=1.96*0.41739 =0.081808 C.I. = (x-bar-E,x-bar+E) = (3.3048-0.0818,3.3048+0.0818) (b) What sample size would be necessary to channelise the true cant over with an error of ± 0.03 grams with 90 part confidence? n=[z*s/E]^2 n=[1.645*0.131989/0.03]^2 = 52.38; rounding up, n=53 (c) Discuss the agentive roles which might source variation in the weight of Tootsie Rolls during manufacture. (Data are from a visit by MBA student hydrogen Scussel.) There are many a(pre noneinal) factors that can influence weight variation in the doing of Tootsie Rolls. The equipment that the Tootsie Rolls are manufactured on co uld be a factor if they are not adjust properly or as required. The speed of the equipment or the al-Quran of the candy that is fed into the sculpturer could also influence the weight. Additionally, in that respect could also be a weight variation if there is a wavering in the temperature. 8.

62 In 1992, the FAA conducted 86,991 pre-employment drug tests on employment applicants who were to be engaged in safety and security-related jobs, and effectuate that 1,143 were positive. (a) Construct a 95 percent confidence interval for the universe proportion of positive drug tests. E = 1.96*sqrt [0.01314*(1-0.01314)/86,991] = 0.0007567.. 95% CI: 0.79615, 83671 (b) Why is the no rmality assumption not a problem, disrespe! ct the very elflike value of p? (Data is from trajectory 120, no. 11 [November 1993], p. 31.) The normality assumption is not a problem because the sample size is very large. Additionally, even though the small value of p, p is normally distributed by the fundamental terminal point Theorem.If you want to get a full essay, piece it on our website: OrderEssay.net

If you want to get a full information about our service, visit our page: write my essay